DAE MATH-212

Applied Mathematics-II

Chapter 3 : Diff. of Trig. & Inverse Trig. Functions

DAE Common Technologies | Second Year

Multiple Choice Questions

Chapter:03 (Diff. of Trig. & Inverse Trig. Functions)

Question 1:

\({\frac{d}{dx}}{Sin{x^3}}=\)

\({Cos{x}^3}\) \(-{Cos{x}^3}\) \(3x{Cos{x}^3}\) \(3{x^2}{Cos{x}^3}\)

Question 2:

\({\frac{d}{dx}}{cos(\frac{1}{x})}=\)

\(-Sin{(\frac{1}{x})}\) \(Sin{(\frac{1}{x})}\) \({\frac{1}{x^2}}Sin{(\frac{1}{x})}\) \(-{\frac{1}{x^2}}Sin{(\frac{1}{x})}\)

Question 3:

\({\frac{d}{dx}}{(Sin ax + Cos ax)}=\)

\(a Cos x + a Sin x\) \(a Cos x - a Sin x\) \(Cos ax + Sin ax\) \(a Cos ax - a Sin ax\)

Question 4:

\({\frac{d}{dx}}{Cosec 3x}=\)

\({-Cosec 3x Cot 3x}\) \({-3 Cosec 3x Cot 3x}\) \(Cot 3x\) \(Cosec 3x\)

Question 5:

\({\frac{d}{dx}}{tan {x^2}}=\)

\(2x{{Sec}^2}{x^2}\) \({{Sec}^2}{x^2}\) \({Sec}{x^2}\) \({tan}{x^2}\)

Question 6:

\({\frac{d}{dx}}{tan(\frac{1}{\sqrt{x}})}=\)

\({{Sec}^2}{\frac{1}{\sqrt{x}}}\) \({{Cosec}^2}{\frac{1}{\sqrt{x}}}\) \({\frac{3}{2\sqrt{x}}}{{Sec}^2}{(\frac{1}{\sqrt{x}})}\) \(-{\frac{1}{2{(x)^{3/2}}}}{{Sec}^2}{(\frac{1}{\sqrt{x}})}\)

Question 7:

\({\frac{dy}{dx}}{(2 Cos 3x)}\)

\({6 Sin 3x}\) \(-{6 Sin 3x}\) \(-{6 Cos 3x}\) \({6 Sec 3x}\)

Question 8:

\({\frac{dy}{dx}}{Sin{\sqrt{x}}}\)

\({cos{\sqrt{x}}}\) \(-{cos{\sqrt{x}}}\) \({\frac{1}{2\sqrt{x}}}{Cos{(\sqrt{x})}}\) \(-{\frac{1}{2\sqrt{x}}}{Cos{(\sqrt{x})}}\)

Question 9:

\({\frac{dy}{dx}}{Sec{3x}}=\)

\({3 Sec 3x tan 3x}\) \({Sec 3x tan 3x}\) \({3 Sec 3x Cot 3x}\) \(-{3 Sec 3x tan 3x}\)

Question 10:

\({\frac{dy}{dx}}{{Sin}^{-1}{x}}=\)

\(-\frac{1}{\sqrt{{x^2}-1}}\) \(\frac{1}{{{Sin}^{-1}x}{\sqrt{1-{x^2}}}}\) \(\frac{{Sin}^{-1}x}{\sqrt{1-{x^2}}}\) \(\frac{1}{\sqrt{1-{x^2}}}\)

NOTE
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INSTRUCTOR
MUHAMMAD BIN JAMEEL
BSC ENGG. CIVIL

PBTE | DAE | MATH-212 APPLIED MATHEMATICS-I | MCQs | Chapter : 03 Diff. of Trig. & Inverse Trig. Functions