PBTE | DAE | MATH-123 APPLIED MATHEMATICS-I | MCQs | Chapter : 07 Phasor Algebra

DAE MATH-123

Contents

1. Applied Mathematics-I
   1. Chapter 7 : Phasor Algebra
   2. Multiple Choice Questions
   3. Chapter:07 (Phasor Algebra)
   4. Question 1:
   5. Question 2:
   6. Question 3:
   7. Question 4:
   8. Question 5:
   9. Question 6:
   10. Question 7:
   11. Question 8:
   12. Question 9:
   13. Question 10:
2. Quiz Results

Applied Mathematics-I

Chapter 7 : Phasor Algebra

DAE Common Technologies | First Year

Multiple Choice Questions

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• Chapter 7 (Phasor Algebra)

Chapter:07 (Phasor Algebra)

Question 1:

The value of ${j^3}E$ is:

jE -jE E -E

Question 2:

The trigonometric form of Z = a + jb is:

|Z|, (cos θ - j sin θ) |Z|, (cos θ + j sin θ) (cos θ + j sin θ) (cos θ - j sin θ)

Question 3:

The trigonometric form of ${e^{-jθ}}$ is:

(cos θ + j sin θ) (cos θ - j sin θ) (cos θ + sin θ) (cos θ - sin θ)

Question 4:

If $2({cos{60^0}-j sin{60^0}})$ then he exponential form is:

$2{e^{j{60^0}}}$ $2{e^{-j{60^0}}}$ $2{e^{60^0}}$ $2{e^{-{60^0}}}$

Question 5:

If $E({cosθ-j sinθ})$ then he exponential form is:

$E{e^{jθ}}$ $E{e^{-jθ}}$ ${e^{jθ}}$ ${e^{-jθ}}$

Question 6:

The trigonometric form of ${1 + j}{\sqrt{3}}$ is:

${2(cos{60^0}-j sin{60^0})}$ ${2(cos{30^0}-j sin{30^0})}$ ${2(cos{60^0}+j sin{60^0})}$ ${2(cos{30^0}+j sin{30^0})}$

Question 7:

The polar form of -1- j is:

${2{\angle}{225^0}}$ ${-2{\angle}{225^0}}$ ${-{\sqrt{2}}{\angle}{225^0}}$ ${{\sqrt{2}}{\angle}{225^0}}$

Question 8:

a + jb form of $2{\angle}{\frac{π}{6}}$ is:

${1+j}{\sqrt{3}}$ ${1-j}{\sqrt{3}}$ ${\sqrt{3}}+j$ ${\sqrt{3}}-j$

Question 9:

Z = 1 – j, then arg Z is:

${45^0}$ ${135^0}$ ${225^0}$ ${315^0}$

Question 10:

${Z_1}=8{\angle}-{30^0}$ and ${Z_2}=8{\angle}-{60^0}$, then ${\frac{Z_1}{Z_2}}$ is:

$4{\angle}{30^0}$ $4{\angle}{-{30^0}}$ $4{\angle}{90^0}$ $4{\angle}{-{90^0}}$

Quiz Results

Total Questions:

Correct Answers:

Incorrect Answers:

Percentage:

NOTE

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INSTRUCTOR

MUHAMMAD BIN JAMEEL

BSC ENGG. CIVIL