DAE MATH-123

Applied Mathematics-I

Chapter 5 : Solution of Triangles

DAE Common Technologies | First Year

Multiple Choice Questions

Chapter:05 (Solution of Triangles)

Question 1:

Law of sines is:

\({\frac{a}{sin A}}={\frac{b}{sin B}}={\frac{c}{sin c}}\) \({\frac{a}{sin A}}={\frac{b}{sin B}}={\frac{c}{sin C}}\) \({\frac{a}{sin B}}={\frac{b}{sin A}}={\frac{c}{sin C}}\) \({\frac{a}{sin B}}={\frac{b}{sin C}}={\frac{a}{sin A}}\)

Question 2:

In a triangle ABC \({\angle}A={70^0}\), \({\angle}B={60^0}\), then \({\angle}C is:\)

\({30^0}\) \({40^0}\) \({50^0}\) \({60^0}\)

Question 3:

When angle of elevation is viewed by an observer, the object is:

Above Below At the same level None of these

Question 4:

If b = 2, A = \(30^0\), B = \(45^0\) , then a is equal to:

\(2\) \({\sqrt{2}}\) \(\frac{\sqrt{3}}{2}\) \(\frac{2}{\sqrt{3}}\)

Question 5:

If a = 2, b = 2, A = \(30^0\), then \(B^0\) is:

\({45^0}\) \({30^0}\) \({60^0}\) \({90^0}\)

Question 6:

If in a triangle ABC, the sides b, c and angle A are given, then the side a is:

\({a^2}={b^2}+{c^2}+2bc .cos A\) \({a^2}={b^2}-{c^2}-2ab .cos A\) \({a^2}={b^2}+{c^2}-2bc .cos A\) \({a^2}={b^2}-{c^2}+2ab .cos A\)

Question 7:

In a triangle ABC, the law of cosine is:

\({Cos A}={\frac{{b^2}+{c^2}+{a^2}}{2bc}}\) \({Cos A}={\frac{{b^2}+{c^2}-{a^2}}{2bc}}\) \({Cos A}={\frac{{b^2}+{c^2}+{a^2}}{2ab}}\) \({Cos A}={\frac{{b^2}+{c^2}-{a^2}}{2ac}}\)

Question 8:

If in a triangle ABC, b = 2, c = 2, A =\({60^0}\), then side a is:

2 3 4 5

Question 9:

If in a triangle ABC, a = 1, b = 2, C = \({60^0}\), then side c is:

\({\sqrt{2}}\) \({2}\) \({1}\) \({3}\)

Question 10:

If in a triangle ABC, b = 2, c = 3, a = 1, then cos A is:

1 2 3 4

NOTE
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INSTRUCTOR
MUHAMMAD BIN JAMEEL
BSC ENGG. CIVIL

PBTE | DAE | MATH-123 APPLIED MATHEMATICS-I | MCQs | Chapter : 05 Solution of Triangles