DAE CH 213 Chapter 3 MCQs

DAE | CH-213

APPLIED CHEMISTRY

CHAPTER : 03

DIPLOMA OF ASSOCIATE ENGINEERING

EXAM PRAPARATION

COMMON WITH:

APPLIED CHEMISTRY

MULTIPLE CHOICE QUESTION

Chapter:03 (Atomic Structure)

Question 1:

The word atom is derived from a Greek word

Particle basic demos atomos

Question 2:

The mass of electron is times of the mass of proton

\(\frac{1}{1834}\) \(\frac{1}{1836}\) \(\frac{1}{1838}\) \(\frac{1}{1840}\)

Question 3:

All the particles present in the nucleus are called

Neutron hypron Anti-nucleon nucleon

Question 4:

The proton was discovered by

J.J.Thomson Goldstein Dalton Chadwick

Question 5:

The atomic number is represented by

A Z N M

Question 6:

The region around the nucleus where probability of finding the electrons is maximum is called

orbit band axis radius

Question 7:

The maximum number of electrons in ‘s’ orbital is

1 2 3 4

Question 8:

The groups present in the periodic table are

6 7 8 9

Question 9:

The periods in the periodic table are

6 7 8 9

Question 10:

The vertical columns in periodic table are called

Periods groups lines series

Question 11:

The horizontal rows in periodic table are

Periods groups lines series

Question 12:

Modern periodic law is based on

Atomic number atomic mass Neutron number nucleons

Question 13:

The valency of all the elements present in same group is

Different multiples variable same

Question 14:

The blocks in the periodic table are.

1 2 3 4

Question 15:

Atomic size, in a group from top to bottom

Increases decreases remain same uncertain

Question 16:

until now elements has been discovered.

109 110 111 112

Question 17:

The smallest particle of an element that takes part in chemical reaction is

An atom a molecule radical a compound

Question 18:

The mass of a neutron is, Kg

\(9.11 x {10^{-31}}\) \(1.6726 x {10^{-27}}\) \(1.67492 x {10^{-27}}\) \(1.67492 x {10^{-28}}\)

Question 19:

The atoms of the same element having same atomic number but different mass number are called

Isotopes isobars isomers polymers

Question 20:

The maximum number of electrons in an orbit is given by formula

\(2{n^1}\) \(2{n^2}\) \(2{n^3}\) \(2{n^4}\)

Quiz Results

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NOTE

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INSTRUCTOR

MUHAMMAD BIN JAMEEL

BSC ENGG. CIVIL